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If you're looking to advance your career, passing the Salesforce JS-Dev-101 Certification Exam is crucial. As with any certification exam, success requires time and effort. While there are many online study materials available, not all of them are accurate or reliable. Many professionals struggle with managing their time and studying effectively, making it difficult to pass the Salesforce Certified JavaScript Developer - Multiple Choice (JS-Dev-101) Exam.
Salesforce JS-Dev-101 Exam Syllabus Topics:
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Quiz 2026 Fantastic JS-Dev-101: Test Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions
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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q27-Q32):
NEW QUESTION # 27
Which option is a core Node,js module?
- A. locate
- B. Path
- C. Memory
- D. Ios
Answer: B
NEW QUESTION # 28
A developer has two ways to write a function:
Option A:
function Monster(){
this.growl = ()=>{
console.log('Grr!');
}
}
Option B:
function Monster(){};
Monster.prototype.growl = ()=>{
console.log('Grr!');
}
After deciding on an option, the developercreates 1000 monster objects.
How many growl methods are created with Option A and Option B?
- A. 1 methods for both
- B. 1000 for both
- C. 1 for Option A, 1000 for Option B
- D. 1000 for Option A, 1 for Option B
Answer: A
NEW QUESTION # 29
Refer to the code below:
01 const server = require('server');
02 /* Insert code here */
A developer imports a library that creates a web server. Theimported library uses events and callbacks to start the servers Which code should be inserted at the line 03 to set up an event and start the web server ?
- A. server()
- B. console.log( 'Listening on ', port) ;
- C. Server.start ();
- D. server.on(' connect ' , ( port) => {console.log('Listening on ' , port) ;})
- E. serve(( port) => (
Answer: D
NEW QUESTION # 30
Code:
01 const sayHello = (name) => {
02 console.log('Hello ', name);
03 };
04
05 const world = () => {
06 return 'World';
07 };
08
09 sayHello(world);
This does not print "Hello World".
What change is needed?
- A. Change line 7 to }();
- B. Change line 2 to console.log('Hello', name());
- C. Change line 5 to function world() {
- D. Change line 9 to sayHello(world)();
Answer: B
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Currently:
sayHello expects a value name and prints it.
world is a function that returns 'World'.
sayHello(world); passes the function object itself, not the result of calling it.
So name inside sayHello is a function, not the string "World".
To keep the call sayHello(world) yet get "World", sayHello must call the function parameter:
const sayHello = (name) => {
console.log('Hello', name());
};
Now:
sayHello(world) passes the function.
Inside sayHello, name() calls world(), which returns "World".
The console logs "Hello World".
Why the others are wrong:
B: Changing line 7 to }(); would attempt to IIFE the function definition and break the declaration.
C: sayHello(world)() would try to call the return value of sayHello, which is undefined, causing an error.
D: Changing world to a function declaration does not change the fact that it is passed as a function reference; sayHello still prints the function object, not 'World'.
________________________________________
NEW QUESTION # 31
Refer to the expression below:
Let x = ('1' + 2) == (6 * 2);
How should this expression be modified to ensure that evaluates to false?
- A. Let x = (1 + 2) == ( '6' / 2);
- B. Let x = ('1' + 2) == ( 6 * 2);
- C. Let x = (1+ 2 ) == ( 6 / 2);
- D. Let x = ('1' + ' 2') == ( 6 * 2);
Answer: B
NEW QUESTION # 32
......
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